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Weighted Mean Slope Given Peak Discharge Of D-h Unit Hydrograph Calculator

Weighted Mean Slope Formula:

\[ S_m = \left( \frac{Q_{pd}}{37.4 \times A^{3/4}} \right)^{3/2} \]

m³/s

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1. What is Weighted Mean Slope?

Weighted Mean Slope derived for peak discharge is calculated by multiplying the weight (or probability) associated with a particular event or outcome. It is an important parameter in hydrological studies for understanding watershed characteristics.

2. How Does the Calculator Work?

The calculator uses the Weighted Mean Slope formula:

\[ S_m = \left( \frac{Q_{pd}}{37.4 \times A^{3/4}} \right)^{3/2} \]

Where:

Explanation: The equation calculates the weighted mean slope based on the peak discharge and catchment area, providing insights into the watershed's hydrological characteristics.

3. Importance of Weighted Mean Slope Calculation

Details: Accurate calculation of weighted mean slope is crucial for hydrological modeling, flood prediction, and watershed management. It helps in understanding the relationship between discharge and catchment characteristics.

4. Using the Calculator

Tips: Enter peak discharge in m³/s and catchment area in m². All values must be valid (greater than 0).

5. Frequently Asked Questions (FAQ)

Q1: What is the significance of the 37.4 constant in the formula?
A: The constant 37.4 is derived from empirical studies and represents the relationship between discharge, area, and slope in hydrological systems.

Q2: How does catchment area affect the weighted mean slope?
A: Larger catchment areas generally result in smaller weighted mean slope values, as the discharge is distributed over a larger area.

Q3: What are typical values for weighted mean slope?
A: Values vary depending on watershed characteristics, but typically range from 0.001 to 0.1 for most hydrological applications.

Q4: Can this formula be used for all types of watersheds?
A: While generally applicable, the formula may need adjustments for extreme topography or unusual hydrological conditions.

Q5: How accurate is this calculation method?
A: The method provides good estimates for most practical applications, but field measurements may be needed for precise engineering designs.

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