Critical Pressure given Clausius parameter a, Reduced and Actual Parameters Calculator

Critical Pressure Formula:

\[ P'_c = \frac{27 \times R^2 \times \left(\frac{T_{rg}}{T_r}\right)^3}{64 \times a} \]

Critical Pressure of Real Gas (Pa):

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is Critical Pressure of Real Gas?

Definition: Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.

Purpose: This calculator helps determine the critical pressure using Clausius parameter a and temperature parameters.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P'_c = \frac{27 \times R^2 \times \left(\frac{T_{rg}}{T_r}\right)^3}{64 \times a} \]

Where:

\( P'_c \) — Critical Pressure of Real Gas (Pascal)
\( R \) — Universal gas constant (8.314 J/mol·K)
\( T_{rg} \) — Temperature of Real Gas (Kelvin)
\( T_r \) — Reduced Temperature (dimensionless)
\( a \) — Clausius parameter a (empirical parameter)

Explanation: The formula relates critical pressure to temperature ratio and Clausius parameter.

3. Importance of Critical Pressure Calculation

Details: Critical pressure is essential for understanding phase behavior and designing processes involving real gases.

4. Using the Calculator

Tips: Enter the temperature of real gas in Kelvin, reduced temperature (dimensionless), and Clausius parameter a. All values must be > 0.

5. Frequently Asked Questions (FAQ)

Q1: What is reduced temperature?
A: Reduced temperature is the ratio of the actual temperature to the critical temperature of the substance.

Q2: How do I obtain Clausius parameter a?
A: Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Q3: What units does this calculator use?
A: Temperature must be in Kelvin, and the result is in Pascals (Pa).

Q4: Why is the universal gas constant squared in the formula?
A: The formula derivation involves gas constant terms that result in R² in the final equation.

Q5: Can this be used for any real gas?
A: Yes, as long as you have the appropriate Clausius parameter for the specific gas.