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Latent Heat of Vaporization given Boiling point of solvent Calculator

Latent Heat of Vaporization Formula:

\[ L_{vaporization} = \frac{[R] \times T_{bp} \times T_{bp}}{1000 \times k_b} \]

K
K·kg/mol

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1. What is Latent Heat of Vaporization?

Definition: The Latent Heat of Vaporization is defined as the heat required to change one mole of liquid at its boiling point under standard atmospheric pressure.

Purpose: This calculator helps determine the energy needed for phase change from liquid to vapor based on solvent properties.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ L_{vaporization} = \frac{[R] \times T_{bp}^2}{1000 \times k_b} \]

Where:

Explanation: The formula relates the boiling point elevation properties of a solvent to its latent heat of vaporization.

3. Importance of Latent Heat Calculation

Details: Knowing the latent heat is crucial for designing distillation systems, understanding phase change thermodynamics, and calculating energy requirements for industrial processes.

4. Using the Calculator

Tips: Enter the solvent boiling point in Kelvin and its ebullioscopic constant (default 0.512 K·kg/mol for water). All values must be > 0.

5. Frequently Asked Questions (FAQ)

Q1: What is the ebullioscopic constant?
A: It's a constant that relates molality to boiling point elevation for a particular solvent.

Q2: What units should I use?
A: Boiling point must be in Kelvin, ebullioscopic constant in K·kg/mol, and the result is in J/kg.

Q3: Can I use this for any solvent?
A: Yes, as long as you know its boiling point and ebullioscopic constant.

Q4: Why is the gas constant divided by 1000?
A: The factor of 1000 converts the result from J/g to J/kg.

Q5: What's a typical value for water?
A: For water at 373.15K, the latent heat is about 2,260,000 J/kg.

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