Mass of Metal to be Deposited Calculator

Electrolysis Formula:

\[ M = \frac{MW \times I \times t}{n \times F} \]

Molecular Weight:

g/mol

Electric Current:

Time:

seconds

N Factor:

Mass to be Deposited (g):

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is the Mass of Metal to be Deposited Calculator?

Definition: This calculator estimates the mass of metal that will be deposited during electrolysis based on Faraday's laws of electrolysis.

Purpose: It helps chemists, electroplaters, and students determine the amount of metal deposited at an electrode during an electrolytic process.

2. How Does the Calculator Work?

The calculator uses Faraday's law of electrolysis:

\[ M = \frac{MW \times I \times t}{n \times F} \]

Where:

\( M \) — Mass of metal deposited (grams)
\( MW \) — Molecular weight of the metal (g/mol)
\( I \) — Electric current (amperes)
\( t \) — Time (seconds)
\( n \) — N factor (moles of electrons per mole of metal)
\( F \) — Faraday constant (96485.33212 C/mol)

Explanation: The formula calculates the mass of metal deposited based on the charge passed through the system and the electrochemical equivalent of the metal.

3. Importance of Mass Calculation in Electrolysis

Details: Accurate mass prediction is crucial for electroplating, metal refining, and electrochemical synthesis to ensure proper coating thickness and material usage.

4. Using the Calculator

Tips: Enter the molecular weight of the metal, current in amperes, time in seconds, and n factor (valence electrons). All values must be > 0.

5. Frequently Asked Questions (FAQ)

Q1: What is the N factor?
A: The N factor represents the number of moles of electrons required to deposit one mole of the metal (equal to the metal's oxidation state in the reaction).

Q2: What is the Faraday constant?
A: It's the electric charge of one mole of electrons (approximately 96,485 coulombs per mole).

Q3: How do I find the molecular weight?
A: The molecular weight can be found on the periodic table for pure elements or calculated by summing atomic weights for compounds.

Q4: Can I use minutes or hours instead of seconds?
A: Yes, but you must convert to seconds first (1 min = 60 sec, 1 hour = 3600 sec).

Q5: Does this account for current efficiency?
A: No, this gives theoretical maximum. Actual deposition may be less due to side reactions and inefficiencies.