Molar Enthalpy of Fusion given Freezing point of solvent Calculator

Molar Enthalpy of Fusion Formula:

\[ \Delta H_{fusion} = \frac{[R] \times T_{fp} \times T_{fp} \times M_{solvent}}{1000 \times k_f} \]

Molar Enthalpy of Fusion (J/mol):

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1. What is Molar Enthalpy of Fusion?

Definition: The Molar Enthalpy of Fusion is the amount of energy needed to change one mole of a substance from the solid phase to the liquid phase at constant temperature and pressure.

Purpose: This calculator determines the molar enthalpy of fusion based on the solvent's freezing point, molar mass, and cryoscopic constant.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ \Delta H_{fusion} = \frac{[R] \times T_{fp}^2 \times M_{solvent}}{1000 \times k_f} \]

Where:

\( \Delta H_{fusion} \) — Molar Enthalpy of Fusion (J/mol)
\( [R] \) — Universal gas constant (8.314 J/mol·K)
\( T_{fp} \) — Solvent Freezing Point (K)
\( M_{solvent} \) — Molar Mass of Solvent (g/mol)
\( k_f \) — Cryoscopic Constant (K·kg/mol)

Explanation: The formula relates the freezing point depression properties of a solvent to its enthalpy of fusion.

3. Importance of Molar Enthalpy of Fusion

Details: Understanding this property is crucial for phase change calculations, thermodynamics studies, and designing processes involving melting or freezing.

4. Using the Calculator

Tips: Enter the solvent's freezing point in Kelvin, molar mass in g/mol, and cryoscopic constant in K·kg/mol. All values must be > 0.

5. Frequently Asked Questions (FAQ)

Q1: What is the cryoscopic constant?
A: It's a constant that describes how much the freezing point of a solvent is depressed when a solute is added.

Q2: Why is the freezing point squared in the formula?
A: The relationship between freezing point and enthalpy of fusion is quadratic, derived from thermodynamic principles.

Q3: What units should I use for molar mass?
A: The calculator expects grams per mole (g/mol) for consistency with the formula.

Q4: Can I use this for any solvent?
A: Yes, as long as you have accurate values for the freezing point, molar mass, and cryoscopic constant.

Q5: How accurate is this calculation?
A: It provides a theoretical value based on ideal conditions. Real-world values may vary slightly.