1. What is Molar Mass of Second Gas by Graham's law?

Definition: This calculator determines the molar mass of an unknown gas using Graham's law of effusion by comparing its effusion rate with a known gas.

Purpose: It's used in chemistry to identify unknown gases or verify molar masses based on their effusion rates.

2. How Does the Calculator Work?

The calculator uses Graham's law formula:

Where:

• \( M_2 \) — Molar mass of second gas (kg/mol)
• \( r_1 \) — Rate of effusion of first gas (m³/s)
• \( r_2 \) — Rate of effusion of second gas (m³/s)
• \( M_1 \) — Molar mass of first gas (kg/mol)

Explanation: The ratio of effusion rates is squared and multiplied by the known molar mass to determine the unknown molar mass.

3. Importance of Graham's Law Calculation

Details: This calculation is fundamental in gas analysis, helping identify unknown gases and understand their behavior under different conditions.

4. Using the Calculator

Tips: Enter the effusion rates for both gases and the molar mass of the known gas. All values must be > 0.

5. Frequently Asked Questions (FAQ)

Q1: What is Graham's law of effusion?
A: It states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

Q2: How do I measure effusion rates?
A: Effusion rates are typically measured by timing how long it takes for a gas to escape through a small hole under controlled conditions.

Q3: What are typical units for molar mass?
A: While kg/mol is the SI unit, g/mol is more commonly used in chemistry (1 kg/mol = 1000 g/mol).

Q4: Can I use this for gas diffusion calculations?
A: Yes, Graham's law applies to both effusion and diffusion, though effusion is more precise for calculations.

Q5: What's a common reference gas?
A: Hydrogen (H₂) with molar mass 0.002016 kg/mol is often used as the known gas.