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Reduced Pressure of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Calculator

Reduced Pressure Formula:

\[ P_r = \frac{P_{gas}}{\frac{3 \cdot R \cdot \frac{T_{gas}}{T_r}}{8 \cdot (c + \frac{V'_m}{V'_{m,r}})}} \]

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1. What is Reduced Pressure of Real Gas?

Definition: Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is a dimensionless quantity used in thermodynamics.

Purpose: This calculator helps determine the reduced pressure of a real gas using the Clausius parameter and other reduced/actual parameters.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P_r = \frac{P_{gas}}{\frac{3 \cdot R \cdot \frac{T_{gas}}{T_r}}{8 \cdot (c + \frac{V'_m}{V'_{m,r}})}} \]

Where:

3. Importance of Reduced Pressure Calculation

Details: Reduced properties are crucial for applying the principle of corresponding states and for comparing different gases under similar conditions.

4. Using the Calculator

Tips: Enter all required parameters. Default values are provided for Clausius parameter (0.0002), molar volume (0.0224 m³), and reduced molar volume (8.96 m³).

5. Frequently Asked Questions (FAQ)

Q1: What is the Clausius parameter c?
A: It's an empirical parameter characteristic to the equation obtained from Clausius model of real gas.

Q2: How do I find reduced temperature?
A: Reduced temperature is the ratio of the actual temperature to the critical temperature of the substance.

Q3: What are typical values for reduced molar volume?
A: Values vary by substance, but often range between 1-10 m³ for many gases at standard conditions.

Q4: Why is reduced pressure important?
A: It allows comparison of different gases' behavior at equivalent states relative to their critical points.

Q5: What units should I use for pressure?
A: The calculator uses Pascals (Pa) for pressure input. Convert from other units if necessary.

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