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Distance of extreme layer from NA given max stress for strut under uniformly distributed load Calculator

Formula Used:

\[ c = \left(\sigma_{bmax} - \frac{P_{axial}}{A_{sectional}}\right) \times \frac{I}{M} \]

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1. What is Distance of Extreme Layer from Neutral Axis?

Definition: This calculator determines the distance from the neutral axis to the extreme layer of a strut under uniformly distributed load, given maximum bending stress and other parameters.

Purpose: It helps structural engineers and designers verify the stress distribution in structural members.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ c = \left(\sigma_{bmax} - \frac{P_{axial}}{A_{sectional}}\right) \times \frac{I}{M} \]

Where:

  • \( c \) — Distance from neutral axis to extreme point (meters)
  • \( \sigma_{bmax} \) — Maximum bending stress (Pascals)
  • \( P_{axial} \) — Axial thrust (Newtons)
  • \( A_{sectional} \) — Cross-sectional area (square meters)
  • \( I \) — Moment of inertia (meters⁴)
  • \( M \) — Maximum bending moment (Newton-meters)

3. Importance of This Calculation

Details: Accurate determination of this distance is crucial for stress analysis, deflection calculations, and ensuring structural safety.

4. Using the Calculator

Tips: Enter all required parameters. The tolerance field (default ±5%) can be adjusted to see the acceptable range of values.

5. Frequently Asked Questions (FAQ)

Q1: What is the neutral axis?
A: The neutral axis is the line in a beam or strut where there is no longitudinal stress when bending occurs.

Q2: Why include axial thrust in the calculation?
A: Axial loads affect the stress distribution and must be considered for accurate results.

Q3: What's a typical tolerance for this calculation?
A: ±5% is common, but this depends on specific engineering requirements.

Q4: How do I find the moment of inertia?
A: It depends on the cross-section shape. Use standard formulas or CAD software.

Q5: Does this apply to all materials?
A: Yes, as long as the material behaves elastically under the applied loads.

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