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Normal Stress on Slice given Shear Strength Calculator

Normal Stress Formula:

\[ \sigma_{normal} = \frac{\tau - c}{\tan(\phi')} + u \]

Pa
Pa
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Pa
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1. What is Normal Stress on a Slice?

Definition: Normal stress (σnormal) is the stress component perpendicular to the plane of interest, calculated based on soil shear strength parameters.

Purpose: This calculation is essential in geotechnical engineering for slope stability analysis and soil mechanics.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ \sigma_{normal} = \frac{\tau - c}{\tan(\phi')} + u \]

Where:

  • σnormal — Normal stress (Pascal)
  • τ — Shear strength of soil (Pascal)
  • c — Cohesion in soil (Pascal)
  • φ' — Effective angle of internal friction (degrees)
  • u — Upward force due to seepage water (Pascal)

Explanation: The formula calculates the normal stress by considering the soil's shear strength minus cohesion, divided by the tangent of the friction angle, plus any upward water pressure.

3. Importance of Normal Stress Calculation

Details: Accurate normal stress calculation is crucial for determining soil stability, designing foundations, and assessing slope failure risks.

4. Using the Calculator

Tips: Enter all required parameters in Pascals (except friction angle in degrees). The tolerance field (default ±5%) allows for practical engineering margins.

5. Frequently Asked Questions (FAQ)

Q1: What is a typical value for cohesion in soil?
A: Cohesion varies greatly: clay may have 10-200 kPa, while sand typically has 0 kPa cohesion.

Q2: How do I determine the effective angle of internal friction?
A: This is typically measured through direct shear tests or triaxial tests in a geotechnical laboratory.

Q3: What does the upward force represent?
A: This accounts for pore water pressure that reduces the effective normal stress in the soil.

Q4: Why include a tolerance percentage?
A: Soil properties are naturally variable; the tolerance provides a practical range for engineering decisions.

Q5: Can this calculator be used for rock mechanics?
A: The principles are similar, but rock typically has different shear strength parameters and may require modified formulas.

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