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Permissible Compressive Stress of Plate Material given Crushing Resistance of Plates Calculator

Permissible Compressive Stress Formula:

\[ \sigma_c = \frac{P_c}{d \times n \times t_1} \]

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1. What is Permissible Compressive Stress of Plate Material?

Definition: This is the maximum compressive stress that the plate material can withstand without failure when subjected to crushing forces from rivets.

Purpose: It helps engineers determine if a plate material is suitable for a given riveted joint application.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ \sigma_c = \frac{P_c}{d \times n \times t_1} \]

Where:

  • \( \sigma_c \) — Permissible compressive stress (Pa)
  • \( P_c \) — Crushing resistance of riveted plate per pitch (N)
  • \( d \) — Diameter of rivet (m)
  • \( n \) — Number of rivets per pitch
  • \( t_1 \) — Thickness of plate 1 (m)

Explanation: The crushing resistance is divided by the product of rivet diameter, number of rivets, and plate thickness to determine the stress.

3. Importance of Compressive Stress Calculation

Details: Proper calculation ensures the plate material can withstand the compressive forces from rivets without deformation or failure.

4. Using the Calculator

Tips: Enter the crushing resistance, rivet diameter, number of rivets per pitch, plate thickness, and tolerance percentage (default ±5%). All values must be > 0 except tolerance which can be 0.

5. Frequently Asked Questions (FAQ)

Q1: What is the typical tolerance for compressive stress?
A: A ±5% tolerance is commonly used, but this can vary based on material specifications and safety requirements.

Q2: How do I determine crushing resistance?
A: Crushing resistance is typically determined through material testing or obtained from material specifications.

Q3: Why include multiple rivets in the calculation?
A: The stress is distributed across all rivets in the pitch length, so more rivets reduce the stress per unit area.

Q4: What units should I use?
A: Use consistent SI units: Newtons for force, meters for length, and Pascals for stress.

Q5: How does plate thickness affect the result?
A: Thicker plates distribute the compressive force over a larger area, reducing the stress.

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