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Area Of Equilateral Triangle Given Exradius Calculator

Formula Used:

\[ A = \frac{r_e^2}{\sqrt{3}} \]

m

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1. What is the Area of Equilateral Triangle given Exradius Formula?

The formula calculates the area of an equilateral triangle when the exradius (radius of the escribed circle) is known. It provides a direct relationship between the exradius and the area of the triangle.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ A = \frac{r_e^2}{\sqrt{3}} \]

Where:

Explanation: The formula derives from the geometric relationship between the exradius and the side length of an equilateral triangle, and subsequently the area.

3. Importance of Area Calculation

Details: Calculating the area of geometric shapes is fundamental in mathematics, engineering, architecture, and various scientific fields. For equilateral triangles, this specific formula provides a quick way to determine area when the exradius is known.

4. Using the Calculator

Tips: Enter the exradius value in meters. The value must be positive and valid. The calculator will compute the area in square meters.

5. Frequently Asked Questions (FAQ)

Q1: What is an exradius in an equilateral triangle?
A: The exradius is the radius of an escribed circle (excircle) of the triangle, which is a circle tangent to one side of the triangle and the extensions of the other two sides.

Q2: How is this formula derived?
A: The formula is derived from the relationship between the exradius and the side length of an equilateral triangle, combined with the standard area formula for an equilateral triangle.

Q3: Can this formula be used for all triangles?
A: No, this specific formula applies only to equilateral triangles where all sides and angles are equal.

Q4: What are the units for the result?
A: The area result is in square meters (m²) if the exradius input is in meters. The units will match the square of the input units.

Q5: How accurate is this calculation?
A: The calculation is mathematically exact based on the input value. The precision depends on the accuracy of the input exradius measurement.

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