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Actual power supplied to hydraulic lift is the actual or the total amount of power that is supplied to the hydraulic lift. It represents the total input power required to operate the hydraulic system.
The calculator uses the formula:
Where:
Explanation: The formula calculates the actual input power required by dividing the useful output power by the efficiency of the hydraulic lift system.
Details: Accurate power calculation is crucial for proper system design, energy efficiency optimization, and ensuring the hydraulic lift operates within its designed power capacity.
Tips: Enter useful power in watts and efficiency as a decimal value between 0 and 1. All values must be valid (power > 0, efficiency between 0-1).
Q1: What is useful power in hydraulic lift?
A: Useful power is the amount of power that is actually used to perform the lifting work in the hydraulic system.
Q2: How is efficiency defined for hydraulic lifts?
A: Efficiency is defined as the ratio between the power output from the hydraulic lift to the input power supplied to it.
Q3: What are typical efficiency values for hydraulic lifts?
A: Efficiency typically ranges from 0.7 to 0.9 (70-90%) for well-designed hydraulic systems, depending on the specific components and design.
Q4: Why is actual power higher than useful power?
A: Actual power is higher due to energy losses in the system, including friction, heat generation, and other inefficiencies in the hydraulic components.
Q5: How can I improve hydraulic lift efficiency?
A: Efficiency can be improved through proper maintenance, using high-quality hydraulic fluids, optimizing component selection, and minimizing leaks and friction losses.