Depth of Flow Given Hydraulic Radius for Triangle Calculator

Formula Used:

\[ d_f(\Delta) = R_H(\Delta) \times \frac{2 \times \sqrt{z_{Tri}^2 + 1}}{z_{Tri}} \]

Depth of Flow of Triangle Channel (d_f):

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1. What is the Depth of Flow Given Hydraulic Radius for Triangle Formula?

The Depth of Flow Given Hydraulic Radius for Triangle formula calculates the depth of flow in a triangular channel based on its hydraulic radius and side slope. This is essential for hydraulic engineering and open channel flow analysis.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ d_f(\Delta) = R_H(\Delta) \times \frac{2 \times \sqrt{z_{Tri}^2 + 1}}{z_{Tri}} \]

Where:

\( d_f(\Delta) \) — Depth of Flow of Triangle Channel (m)
\( R_H(\Delta) \) — Hydraulic Radius of Triangular Channel (m)
\( z_{Tri} \) — Side Slope of Triangular Channel (dimensionless)

Explanation: The formula relates the hydraulic radius and side slope to determine the depth of flow in a triangular channel section.

3. Importance of Depth of Flow Calculation

Details: Accurate depth of flow calculation is crucial for designing efficient drainage systems, irrigation channels, and understanding flow characteristics in triangular channels.

4. Using the Calculator

Tips: Enter hydraulic radius in meters and side slope as a dimensionless value. Both values must be positive numbers greater than zero.

5. Frequently Asked Questions (FAQ)

Q1: What is hydraulic radius in a triangular channel?
A: Hydraulic radius is the ratio of the cross-sectional area of flow to the wetted perimeter in a triangular channel.

Q2: How is side slope defined for triangular channels?
A: Side slope represents the horizontal distance per unit vertical drop of the channel sides (e.g., z:1 where z is horizontal and 1 is vertical).

Q3: What are typical applications of this calculation?
A: This calculation is used in irrigation systems, drainage design, and hydraulic engineering projects involving triangular channels.

Q4: Are there limitations to this formula?
A: This formula assumes uniform flow conditions and may not be accurate for rapidly varying flow or non-uniform channel sections.

Q5: Can this formula be used for other channel shapes?
A: No, this specific formula is designed for triangular channels only. Other channel shapes have different hydraulic relationships.