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Depth of Flow Using Absolute Velocity of Surge When Flow Is Completely Stopped Calculator

Formula Used:

\[ h_1 = \frac{v_{abs}}{v_{abs} - V_{Negative\ surges}} \times D_2 \]

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1. What is Depth of Flow Using Absolute Velocity of Surge When Flow Is Completely Stopped?

This calculation determines the depth of point 1 below the free surface in a static mass of liquid when flow is completely stopped, using the absolute velocity of surge and velocity of fluid at negative surges.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ h_1 = \frac{v_{abs}}{v_{abs} - V_{Negative\ surges}} \times D_2 \]

Where:

Explanation: This formula calculates the depth relationship between two points in a fluid system when flow is completely stopped, using velocity parameters.

3. Importance of Depth Calculation

Details: Accurate depth calculation is crucial for hydraulic engineering, fluid dynamics analysis, and designing water management systems where flow cessation occurs.

4. Using the Calculator

Tips: Enter absolute velocity in m/s, velocity at negative surges in m/s, and depth of point 2 in meters. All values must be positive, and absolute velocity should be greater than negative surge velocity to avoid division by zero.

5. Frequently Asked Questions (FAQ)

Q1: What is absolute velocity of issuing jet?
A: Absolute velocity of issuing jet refers to the actual velocity of the jet used in propeller systems, measured relative to a fixed reference point.

Q2: What are negative surges in fluid flow?
A: Negative surges refer to the backward movement or reduction in flow velocity that occurs when flow is suddenly stopped or interrupted.

Q3: When is this calculation typically used?
A: This calculation is used in hydraulic engineering, dam design, pipeline systems, and any application where sudden flow stoppage needs to be analyzed.

Q4: What happens if vabs equals VNegative surges?
A: If absolute velocity equals velocity at negative surges, the denominator becomes zero, making the result undefined as it would cause division by zero.

Q5: Are there limitations to this formula?
A: This formula assumes ideal fluid conditions and may need adjustments for real-world applications with friction losses, turbulence, and other non-ideal factors.

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