Depth of Water in 2nd Well given Coefficient of Transmissibility Calculator

Formula Used:

\[ h_2 = h_1 + \frac{Q \cdot \log_{10}(r_2 / r_1)}{2.72 \cdot T} \]

Depth of Water 1 (h1):

Discharge (Q):

m³/s

Radial Distance at Observation Well 2 (r2):

Radial Distance at Observation Well 1 (r1):

Coefficient of Transmissibility (T):

m²/s

Depth of Water 2 (h2):

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1. What is the Depth of Water in 2nd Well Calculation?

This calculation determines the depth of water in a second observation well based on the coefficient of transmissibility and other hydraulic parameters. It's essential for groundwater flow analysis and aquifer characterization.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ h_2 = h_1 + \frac{Q \cdot \log_{10}(r_2 / r_1)}{2.72 \cdot T} \]

Where:

\( h_2 \) — Depth of water in 2nd well (m)
\( h_1 \) — Depth of water in 1st well (m)
\( Q \) — Discharge rate (m³/s)
\( r_2 \) — Radial distance at observation well 2 (m)
\( r_1 \) — Radial distance at observation well 1 (m)
\( T \) — Coefficient of transmissibility (m²/s)

Explanation: This formula calculates the water depth in the second well based on logarithmic relationship between radial distances and the transmissibility coefficient.

3. Importance of Water Depth Calculation

Details: Accurate water depth calculation is crucial for groundwater resource management, well design, and understanding aquifer behavior under pumping conditions.

4. Using the Calculator

Tips: Enter all values in appropriate units. Ensure radial distances are measured from the pumping well center, and all values are positive with proper relationships (r2 > r1).

5. Frequently Asked Questions (FAQ)

Q1: What is the coefficient of transmissibility?
A: The coefficient of transmissibility represents the rate of water flow through a vertical strip of aquifer under unit hydraulic gradient.

Q2: Why use logarithmic function in this calculation?
A: The logarithmic function accounts for the radial flow pattern around pumping wells, where drawdown decreases logarithmically with distance.

Q3: What are typical values for coefficient of transmissibility?
A: Values vary widely depending on aquifer material, ranging from 10⁻⁵ to 10⁻¹ m²/s for different geological formations.

Q4: When is this calculation most applicable?
A: This calculation is most applicable for confined aquifers under steady-state pumping conditions with fully penetrating wells.

Q5: What are the limitations of this approach?
A: This approach assumes homogeneous, isotropic aquifer conditions and may not accurately represent complex geological settings or transient conditions.