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Diameter Of Particle Given Maximum Critical Scour Velocity Calculator

Formula Used:

\[ D = \left( \frac{v_{maxs}}{4.5 \times \sqrt{g \times (G - 1)}} \right)^2 \]

m/s
m/s²

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1. What is the Diameter of Particle Calculation?

The diameter of particle calculation determines the size of sediment particles that can be moved or eroded by a fluid flow at its maximum critical scour velocity. This is important in sediment transport studies and hydraulic engineering applications.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ D = \left( \frac{v_{maxs}}{4.5 \times \sqrt{g \times (G - 1)}} \right)^2 \]

Where:

Explanation: The formula calculates the particle diameter based on the maximum velocity at which scour occurs, gravitational acceleration, and the specific gravity of the particle material.

3. Importance of Particle Diameter Calculation

Details: Accurate particle diameter calculation is crucial for designing stable hydraulic structures, predicting sediment transport, and preventing erosion in rivers, channels, and coastal areas.

4. Using the Calculator

Tips: Enter maximum critical scour velocity in m/s, acceleration due to gravity in m/s² (default is 9.8 m/s²), and specific gravity of particle. All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What is maximum critical scour velocity?
A: Maximum critical scour velocity is the highest flow velocity at which sediment particles begin to move or become eroded from the bed surface.

Q2: Why is specific gravity important in this calculation?
A: Specific gravity accounts for the density difference between the particle material and water, which affects the particle's susceptibility to movement by fluid flow.

Q3: What are typical values for specific gravity of sediment particles?
A: For most natural sediments (sand, gravel), specific gravity ranges from 2.6 to 2.7. For heavier minerals, it can be higher.

Q4: How accurate is this formula for different particle shapes?
A: The formula assumes spherical particles. For non-spherical particles, the results should be considered as equivalent spherical diameters.

Q5: What are the limitations of this calculation?
A: The formula may be less accurate for very fine particles (clays) or very coarse particles where other factors like particle interlocking become significant.

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