Discharge Per Unit Width Of Channel Given Conjugate Depths Calculator

Formula Used:

\[ q = \sqrt{(d_{1R} \times d_{2R} \times (d_{1R} + d_{2R}) \times g \times 0.5)} \]

Discharge per Unit Width:

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is Discharge Per Unit Width?

Discharge per unit width is the ratio of total discharge in the channel to the width considered. It represents the volume flow rate of water per unit width of the channel cross-section.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ q = \sqrt{(d_{1R} \times d_{2R} \times (d_{1R} + d_{2R}) \times g \times 0.5)} \]

Where:

\( q \) — Discharge per unit width (m²/s)
\( d_{1R} \) — Depth of point 1 for rectangular channel (m)
\( d_{2R} \) — Depth of point 2 for rectangular channel (m)
\( g \) — Gravitational acceleration (9.80665 m/s²)

Explanation: This formula calculates the discharge per unit width based on conjugate depths in a rectangular channel, considering gravitational effects.

3. Importance of Discharge Calculation

Details: Accurate discharge calculation is crucial for hydraulic engineering, flood control, irrigation system design, and environmental flow management in open channels.

4. Using the Calculator

Tips: Enter both depth values in meters. All values must be positive and valid for accurate calculation results.

5. Frequently Asked Questions (FAQ)

Q1: What are conjugate depths in open channel flow?
A: Conjugate depths refer to the two possible depths that occur before and after a hydraulic jump in an open channel, having the same specific force.

Q2: When is this formula applicable?
A: This formula is specifically applicable for rectangular channels where conjugate depths are known and the flow is undergoing a hydraulic jump.

Q3: What units should be used for input values?
A: Both depth values should be entered in meters (m) for consistent results with the gravitational constant in m/s².

Q4: Are there limitations to this equation?
A: This equation assumes a rectangular channel cross-section and may not be accurate for other channel shapes or under extreme flow conditions.

Q5: How accurate is this calculation?
A: The calculation provides theoretical results based on standard hydraulic principles. Actual field conditions may vary due to factors like channel roughness and turbulence.