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Load On Screw Given Collar Friction Torque According To Uniform Pressure Theory Calculator

Formula Used:

\[ W = \frac{3 \times T_c \times (D_o^2 - D_i^2)}{\mu_{collar} \times (D_o^3 - D_i^3)} \]

N·m
m
m

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1. What is Load on Screw given Collar Friction Torque?

This calculation determines the axial load on a power screw based on collar friction torque, collar dimensions, and friction coefficient under uniform pressure theory. It's essential for mechanical design and analysis of screw mechanisms.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ W = \frac{3 \times T_c \times (D_o^2 - D_i^2)}{\mu_{collar} \times (D_o^3 - D_i^3)} \]

Where:

Explanation: This formula calculates the axial load that a screw can support based on the friction torque at the collar, assuming uniform pressure distribution.

3. Importance of Load Calculation

Details: Accurate load calculation is crucial for designing power screws in various mechanical applications, ensuring proper sizing, and preventing mechanical failure.

4. Using the Calculator

Tips: Enter collar friction torque in N·m, diameters in meters, and friction coefficient. All values must be positive, and outer diameter must be greater than inner diameter.

5. Frequently Asked Questions (FAQ)

Q1: What is uniform pressure theory?
A: Uniform pressure theory assumes that the pressure distribution between contacting surfaces is uniform, which simplifies friction calculations.

Q2: When is this calculation applicable?
A: This calculation is used for power screws with collar bearings where friction torque is known and uniform pressure distribution can be assumed.

Q3: What are typical values for coefficient of friction?
A: Coefficient of friction values typically range from 0.1 to 0.3 for well-lubricated metal surfaces, and higher for dry or rough surfaces.

Q4: How does collar design affect load capacity?
A: Larger diameter collars generally provide higher load capacity, but also increase friction torque requirements.

Q5: What are the limitations of this formula?
A: This formula assumes ideal conditions, uniform pressure distribution, and may not account for wear, temperature effects, or non-uniform loading.

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