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Loss Of Pressure Head For Viscous Flow Through Circular Pipe Calculator

Formula Used:

\[ h_f = \frac{32 \times \mu \times V \times L}{\rho \times [g] \times D_p^2} \]

Pa·s
m/s
m
kg/m³
m

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1. What is Loss of Pressure Head for Viscous Flow?

Loss of Peizometric Head is considered in the viscous flow through circular pipe. It represents the energy loss due to fluid viscosity as the fluid flows through the pipe system.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ h_f = \frac{32 \times \mu \times V \times L}{\rho \times [g] \times D_p^2} \]

Where:

Explanation: This formula calculates the head loss due to viscous effects in laminar flow through circular pipes, derived from the Hagen-Poiseuille equation.

3. Importance of Pressure Head Calculation

Details: Accurate calculation of pressure head loss is crucial for designing piping systems, determining pump requirements, and ensuring efficient fluid transport in various engineering applications.

4. Using the Calculator

Tips: Enter all values in appropriate SI units. Viscosity in Pa·s, velocity in m/s, length in m, density in kg/m³, and diameter in m. All values must be positive.

5. Frequently Asked Questions (FAQ)

Q1: What is the range of validity for this formula?
A: This formula is valid for laminar flow conditions (Reynolds number < 2300) through straight circular pipes.

Q2: How does viscosity affect pressure head loss?
A: Higher viscosity fluids experience greater resistance to flow, resulting in higher pressure head losses for the same flow conditions.

Q3: What happens if the flow is turbulent?
A: This formula is not applicable for turbulent flow. Different empirical correlations (like Darcy-Weisbach equation) must be used for turbulent flow conditions.

Q4: Why is pipe diameter squared in the denominator?
A: The diameter appears squared because the cross-sectional area of the pipe is proportional to diameter squared, and larger diameters significantly reduce flow resistance.

Q5: Can this formula be used for non-circular pipes?
A: No, this specific formula is derived for circular pipes. For non-circular conduits, the hydraulic diameter concept must be used with appropriate modifications.

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