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Maximum Phase Voltage between Outer and Neutral Wire (2-Phase 3-Wire US) Calculator

Formula Used:

\[ V_{m(phase)} = \frac{V_m}{\sqrt{2}} \]

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1. What is Maximum Phase Voltage between Outer and Neutral Wire?

Peak Phase Voltage is the maximum amplitude of the phase voltage between outer and neutral wire in a 2-Phase 3-Wire US electrical system. It represents the highest voltage level that occurs during the AC cycle.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ V_{m(phase)} = \frac{V_m}{\sqrt{2}} \]

Where:

Explanation: This formula converts the maximum AC voltage to the peak phase voltage by dividing by the square root of 2, which is the relationship between RMS and peak values in AC systems.

3. Importance of Peak Phase Voltage Calculation

Details: Accurate calculation of peak phase voltage is crucial for proper insulation design, equipment selection, and safety considerations in 2-Phase 3-Wire US electrical systems.

4. Using the Calculator

Tips: Enter the maximum voltage underground AC in volts. The value must be positive and greater than zero.

5. Frequently Asked Questions (FAQ)

Q1: What is the difference between maximum voltage and peak phase voltage?
A: Maximum voltage refers to the highest voltage level in the AC system, while peak phase voltage specifically refers to the maximum amplitude between outer and neutral wire in the phase voltage.

Q2: Why divide by √2 in the calculation?
A: The division by √2 converts the maximum (RMS) voltage to the peak voltage, as the relationship between RMS and peak values in AC systems is V_peak = V_rms × √2.

Q3: What are typical voltage values for 2-Phase 3-Wire US systems?
A: Typical systems operate at 120/240V or 120/208V, with maximum voltages ranging from 170V to 340V depending on the specific system configuration.

Q4: Is this calculation specific to underground AC systems?
A: While the formula is general for AC systems, this calculator is specifically designed for underground AC applications in the 2-Phase 3-Wire US configuration.

Q5: How accurate is this calculation for real-world applications?
A: The calculation provides theoretical values based on ideal conditions. Actual voltages may vary due to system losses, load variations, and other practical factors.

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