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Modulus of Rigidity with Known Torsional Rigidity Calculator

Modulus of Rigidity Formula:

\[ G = \frac{TJ}{J} \]

N·m²
m⁴

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1. What is Modulus of Rigidity?

Modulus of Rigidity (also known as Shear Modulus) is the measure of the rigidity of a body, given by the ratio of shear stress to shear strain. It is often denoted by G and is an important property in materials science and engineering.

2. How Does the Calculator Work?

The calculator uses the Modulus of Rigidity formula:

\[ G = \frac{TJ}{J} \]

Where:

Explanation: The formula calculates the modulus of rigidity by dividing the torsional rigidity by the polar moment of inertia of the material.

3. Importance of Modulus of Rigidity Calculation

Details: Accurate calculation of modulus of rigidity is crucial for designing mechanical components subjected to torsional loads, analyzing material behavior under shear stress, and ensuring structural integrity in engineering applications.

4. Using the Calculator

Tips: Enter torsional rigidity in N·m² and polar moment of inertia in m⁴. Both values must be positive numbers greater than zero.

5. Frequently Asked Questions (FAQ)

Q1: What is the physical significance of Modulus of Rigidity?
A: Modulus of Rigidity represents a material's resistance to shearing deformation. Higher values indicate stiffer materials that resist shear deformation more effectively.

Q2: How does Modulus of Rigidity differ from Young's Modulus?
A: Young's Modulus measures resistance to linear deformation (tension/compression), while Modulus of Rigidity measures resistance to shear deformation (sliding of layers).

Q3: What are typical values of Modulus of Rigidity for common materials?
A: Steel: ~80 GPa, Aluminum: ~26 GPa, Rubber: ~0.0003 GPa. Values vary significantly depending on material composition and treatment.

Q4: When is this calculation particularly important?
A: This calculation is critical in designing shafts, springs, and other components subjected to torsional loads in mechanical engineering applications.

Q5: Are there limitations to this formula?
A: This formula assumes homogeneous, isotropic materials and linear elastic behavior. It may not accurately predict behavior for anisotropic materials or under large deformations.

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