Home
Back
Formula Used:
| From: | To: |
The output voltage of a Common Source (CS) Amplifier is the amplified voltage signal obtained at the drain terminal when an input signal is applied to the gate terminal. It represents the voltage gain achieved by the amplifier circuit.
The calculator uses the formula:
Where:
Explanation: The output voltage is directly proportional to the transconductance of the transistor, the gate-to-source voltage, and the load resistance in the circuit.
Details: Calculating the output voltage is essential for designing and analyzing amplifier circuits, determining voltage gain, and ensuring proper signal amplification in electronic systems.
Tips: Enter transconductance in Siemens, gate-to-source voltage in Volts, and load resistance in Ohms. All values must be positive numbers greater than zero.
Q1: What is transconductance in a CS amplifier?
A: Transconductance (g_m) is the ratio of the change in drain current to the change in gate-to-source voltage, representing the amplification capability of the transistor.
Q2: How does load resistance affect output voltage?
A: Higher load resistance results in higher output voltage, as the voltage drop across the resistance increases with larger current flow.
Q3: What are typical values for transconductance?
A: Transconductance values typically range from millisiemens (mS) to several siemens, depending on the transistor type and operating conditions.
Q4: Can this formula be used for all CS amplifiers?
A: This formula provides a basic calculation for ideal CS amplifiers. Real-world implementations may require additional considerations for parasitic elements and non-ideal behavior.
Q5: How does gate-to-source voltage affect amplification?
A: The gate-to-source voltage controls the conduction of the transistor, with higher voltages typically resulting in greater current flow and thus higher output voltage.