Power Required To Drive Double Acting Reciprocating Pump Calculator

Formula Used:

\[ Power = \frac{2 \times \gamma \times A_p \times L \times N \times (h_s + h_d)}{60} \]

Specific Weight (γ):

N/m³

Area of Piston (Aₚ):

m²

Length of Stroke (L):

Speed (N):

rpm

Height of Centre of Cylinder (hₛ):

Height to Which Liquid is Raised (h_d):

Power (P):

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1. What is the Power Required to Drive Double Acting Reciprocating Pump?

The power required to drive a double acting reciprocating pump is the amount of energy needed per second to operate the pump, taking into account the specific weight of the liquid, piston area, stroke length, pump speed, and the heights involved in the pumping process.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ Power = \frac{2 \times \gamma \times A_p \times L \times N \times (h_s + h_d)}{60} \]

Where:

\( \gamma \) — Specific Weight (N/m³)
\( A_p \) — Area of Piston (m²)
\( L \) — Length of Stroke (m)
\( N \) — Speed (rpm)
\( h_s \) — Height of Centre of Cylinder (m)
\( h_d \) — Height to Which Liquid is Raised (m)

Explanation: The formula calculates the power required by considering the work done in both directions of the piston stroke (double acting) and the total head against which the pump is working.

3. Importance of Power Calculation

Details: Accurate power calculation is essential for proper pump selection, motor sizing, energy efficiency assessment, and cost estimation in pumping system design and operation.

4. Using the Calculator

Tips: Enter all values in appropriate units. Specific weight should be in N/m³, areas in m², lengths in meters, and speed in rpm. All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What is specific weight and how is it different from density?
A: Specific weight is weight per unit volume (N/m³), while density is mass per unit volume (kg/m³). They are related by γ = ρ × g, where g is gravitational acceleration.

Q2: Why is there a factor of 2 in the formula?
A: The factor of 2 accounts for the double-acting nature of the pump, where work is done during both forward and return strokes.

Q3: What are typical values for specific weight of common liquids?
A: Water: 9810 N/m³, Oil: 8000-9000 N/m³, Mercury: 133100 N/m³. The specific weight varies with temperature.

Q4: How does stroke length affect power requirement?
A: Longer stroke length increases the volume displaced per stroke, which increases the power requirement proportionally.

Q5: Is this formula applicable to single-acting pumps?
A: For single-acting pumps, remove the factor of 2 from the numerator, as work is done only during one stroke.