Power Transmitted Using Area Of X-Section (1-Phase 2-Wire Mid-Point Earthed) Calculator

Formula Used:

\[ P = \sqrt{\frac{A \times P_{\text{loss}} \times (V_m \times \cos(\Phi))^2}{4 \times \rho \times L}} \]

Area of Underground AC Wire (A):

m²

Line Losses (P_loss):

Maximum Voltage Underground AC (V_m):

Phase Difference (Φ):

rad

Resistivity (ρ):

Ω·m

Length of Underground AC Wire (L):

Power Transmitted (P):

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1. What is Power Transmitted Using Area Of X-Section?

The power transmitted using area of cross-section formula calculates the amount of electrical power that can be transferred through an underground AC wire system, taking into account various electrical and physical parameters of the transmission system.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P = \sqrt{\frac{A \times P_{\text{loss}} \times (V_m \times \cos(\Phi))^2}{4 \times \rho \times L}} \]

Where:

\( P \) — Power Transmitted (W)
\( A \) — Area of Underground AC Wire (m²)
\( P_{\text{loss}} \) — Line Losses (W)
\( V_m \) — Maximum Voltage Underground AC (V)
\( \cos(\Phi) \) — Cosine of Phase Difference
\( \rho \) — Resistivity (Ω·m)
\( L \) — Length of Underground AC Wire (m)

Explanation: The formula calculates the maximum power that can be transmitted through an underground AC wire system while accounting for electrical losses, voltage levels, and material properties.

3. Importance of Power Transmission Calculation

Details: Accurate power transmission calculation is crucial for designing efficient electrical distribution systems, minimizing energy losses, and ensuring proper sizing of electrical components for optimal performance.

4. Using the Calculator

Tips: Enter all values in appropriate units. Ensure positive values for all parameters. Phase difference should be entered in radians. All values must be valid and greater than zero.

5. Frequently Asked Questions (FAQ)

Q1: Why is cross-sectional area important in power transmission?
A: Larger cross-sectional area reduces resistance, which decreases power losses and allows for more efficient power transmission over longer distances.

Q2: What factors affect line losses in underground AC systems?
A: Line losses are affected by conductor material, cross-sectional area, length of the wire, current magnitude, and operating temperature.

Q3: How does phase difference affect power transmission?
A: Phase difference between voltage and current affects the power factor, which determines the ratio of real power to apparent power in the system.

Q4: What is the significance of resistivity in power transmission?
A: Resistivity determines how strongly a material opposes current flow. Lower resistivity materials (like copper) are preferred for power transmission to minimize losses.

Q5: When should this calculation be used?
A: This calculation is essential for electrical engineers designing underground power distribution systems, determining appropriate wire sizes, and optimizing system efficiency.