Power Transmitted Using Area Of X-Section(2-Phase 4-Wire OS) Calculator

Formula Used:

\[ P = \sqrt{\frac{2 \times A \times (V_m^2) \times P_{loss} \times (\cos(\Phi))^2}{\rho \times L}} \]

Area of Overhead AC Wire (A):

m²

Maximum Voltage Overhead AC (V_m):

Line Losses (P_loss):

Phase Difference (Φ):

rad

Resistivity (ρ):

Ω·m

Length of Overhead AC Wire (L):

Power Transmitted (P):

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is Power Transmitted Using Area Of X-Section?

This calculator determines the power transmitted through a 2-phase 4-wire overhead system using the cross-sectional area of the wire and other electrical parameters. It's essential for designing efficient power transmission systems.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P = \sqrt{\frac{2 \times A \times (V_m^2) \times P_{loss} \times (\cos(\Phi))^2}{\rho \times L}} \]

Where:

\( P \) — Power Transmitted (W)
\( A \) — Area of Overhead AC Wire (m²)
\( V_m \) — Maximum Voltage Overhead AC (V)
\( P_{loss} \) — Line Losses (W)
\( \Phi \) — Phase Difference (rad)
\( \rho \) — Resistivity (Ω·m)
\( L \) — Length of Overhead AC Wire (m)

Explanation: This formula calculates the maximum power that can be transmitted through a 2-phase 4-wire overhead system while accounting for line losses and phase differences.

3. Importance of Power Transmission Calculation

Details: Accurate power transmission calculation is crucial for designing efficient electrical distribution systems, minimizing energy losses, and ensuring proper voltage regulation across the network.

4. Using the Calculator

Tips: Enter all values in appropriate units. Ensure positive values for all parameters. Phase difference should be in radians (0 to π/2 for typical power systems).

5. Frequently Asked Questions (FAQ)

Q1: Why is cross-sectional area important in power transmission?
A: Larger cross-sectional area reduces resistance, which decreases power losses and allows for more efficient power transmission over longer distances.

Q2: What affects line losses in overhead systems?
A: Line losses are affected by conductor resistance, current magnitude, transmission distance, and environmental factors like temperature.

Q3: How does phase difference affect power transmission?
A: Phase difference (power factor) affects the real power component. Lower power factors result in higher losses for the same apparent power.

Q4: What is typical resistivity for overhead conductors?
A: Copper: ~1.68×10⁻⁸ Ω·m, Aluminum: ~2.82×10⁻⁸ Ω·m. Actual values may vary based on conductor composition and temperature.

Q5: When is this calculation most relevant?
A: This calculation is essential during the design phase of overhead power transmission systems to optimize conductor size and minimize energy losses.