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Power Transmitted using Area of X-Section(3-Phase 3-Wire OS) Calculator

Formula Used:

\[ P = \sqrt{\frac{3 \times A \times V_m^2 \times P_{\text{loss}} \times (\cos(\Phi))^2}{\rho \times 2 \times L}} \]

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1. What is Power Transmitted using Area of X-Section?

Power Transmitted using Area of X-Section calculates the amount of electrical power that can be transmitted through a 3-phase 3-wire overhead system based on the cross-sectional area of the wire and other electrical parameters.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P = \sqrt{\frac{3 \times A \times V_m^2 \times P_{\text{loss}} \times (\cos(\Phi))^2}{\rho \times 2 \times L}} \]

Where:

Explanation: This formula calculates the maximum power that can be transmitted through an overhead AC wire system while accounting for line losses, voltage, and material properties.

3. Importance of Power Transmission Calculation

Details: Accurate power transmission calculation is crucial for designing efficient electrical distribution systems, minimizing energy losses, and ensuring proper sizing of electrical components.

4. Using the Calculator

Tips: Enter all values in appropriate units. Ensure positive values for all parameters. Phase difference should be in radians (0 to π/2 for typical power systems).

5. Frequently Asked Questions (FAQ)

Q1: Why is cross-sectional area important in power transmission?
A: Larger cross-sectional area reduces resistance, which decreases power losses and allows for more efficient power transmission over longer distances.

Q2: How does phase difference affect power transmission?
A: Phase difference (power factor) affects the real power component. A higher power factor (closer to 1) means more efficient power transmission.

Q3: What are typical resistivity values for overhead wires?
A: Copper: ~1.68×10⁻⁸ Ω·m, Aluminum: ~2.82×10⁻⁸ Ω·m. Actual values may vary based on material purity and temperature.

Q4: How do line losses affect power transmission efficiency?
A: Higher line losses mean less efficient power transmission, as more energy is dissipated as heat rather than delivered to the load.

Q5: What is the significance of maximum voltage in this calculation?
A: Higher voltages allow for more power transmission with lower current, reducing I²R losses and enabling more efficient long-distance transmission.

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