Power Transmitted Using Line Losses(Two-Wire Mid-Point Earthed) Calculator

Power Transmitted using Line Losses (Two-Wire Mid-Point Earthed) Formula:

\[ P = V_m \times \sqrt{\frac{P_{loss} \times 2 \times A}{\rho \times L}} \]

Maximum Voltage Overhead DC (V_m):

Volt

Line Losses (P_loss):

Watt

Area of Overhead DC Wire (A):

m²

Resistivity (ρ):

Ω·m

Length of Wire DC (L):

Power Transmitted (P):

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1. What is Power Transmitted using Line Losses (Two-Wire Mid-Point Earthed)?

Power Transmitted using Line Losses (Two-Wire Mid-Point Earthed) calculates the power transmitted in a two-wire DC system with mid-point earthing, considering line losses, maximum voltage, wire area, resistivity, and length. It provides an accurate assessment of power transmission efficiency in such systems.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P = V_m \times \sqrt{\frac{P_{loss} \times 2 \times A}{\rho \times L}} \]

Where:

\( P \) — Power Transmitted (Watt)
\( V_m \) — Maximum Voltage Overhead DC (Volt)
\( P_{loss} \) — Line Losses (Watt)
\( A \) — Area of Overhead DC Wire (m²)
\( \rho \) — Resistivity (Ω·m)
\( L \) — Length of Wire DC (m)

Explanation: The formula accounts for the relationship between power transmitted, voltage, line losses, and the physical properties of the transmission wire in a two-wire mid-point earthed DC system.

3. Importance of Power Transmitted Calculation

Details: Accurate power transmitted calculation is crucial for designing efficient DC power transmission systems, optimizing energy efficiency, and minimizing power losses in two-wire mid-point earthed configurations.

4. Using the Calculator

Tips: Enter maximum voltage in volts, line losses in watts, wire area in square meters, resistivity in ohm-meters, and wire length in meters. All values must be valid positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What is a two-wire mid-point earthed system?
A: A two-wire mid-point earthed system is a DC power transmission configuration where the midpoint of the supply is grounded, providing balanced voltage distribution and improved safety.

Q2: Why is resistivity important in power transmission?
A: Resistivity determines how much a material opposes current flow, directly affecting line losses and efficiency in power transmission systems.

Q3: How do line losses affect power transmission efficiency?
A: Line losses represent energy dissipated as heat in the transmission wires, reducing the overall efficiency of power delivery from source to load.

Q4: What factors influence the maximum voltage in DC transmission?
A: Maximum voltage is determined by insulation capabilities, safety regulations, and the specific requirements of the electrical system being designed.

Q5: When should this calculation be used?
A: This calculation is specifically designed for two-wire DC transmission systems with mid-point earthing, commonly used in certain industrial and specialized power applications.