Power Transmitted using Load Current (2 Phase 4 Wire US) Calculator

Formula Used:

\[ P = \frac{I \times V_m \times \cos(\Phi)}{\sqrt{2}} \]

Current Underground AC (I):

Ampere

Maximum Voltage Underground AC (Vm):

Volt

Phase Difference (Φ):

Radian

Power Transmitted (P):

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1. What is Power Transmitted using Load Current?

Power Transmitted using Load Current refers to the amount of electrical power that is transferred through a 2-phase 4-wire underground AC system, calculated based on the load current, maximum voltage, and phase difference.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P = \frac{I \times V_m \times \cos(\Phi)}{\sqrt{2}} \]

Where:

\( P \) — Power Transmitted (Watt)
\( I \) — Current Underground AC (Ampere)
\( V_m \) — Maximum Voltage Underground AC (Volt)
\( \Phi \) — Phase Difference (Radian)
\( \cos \) — Cosine function
\( \sqrt{2} \) — Square root of 2

Explanation: This formula calculates the real power transmitted in a 2-phase 4-wire AC system, accounting for the phase difference between voltage and current.

3. Importance of Power Calculation

Details: Accurate power calculation is essential for designing efficient electrical systems, determining energy consumption, and ensuring proper sizing of electrical components in underground AC transmission systems.

4. Using the Calculator

Tips: Enter current in amperes, maximum voltage in volts, and phase difference in radians. All values must be valid positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: Why is the square root of 2 used in the formula?
A: The square root of 2 factor converts the maximum voltage to RMS voltage in AC calculations.

Q2: What is the significance of phase difference in power calculation?
A: Phase difference affects the power factor, which determines how effectively electrical power is being converted into useful work.

Q3: When should this calculation be used?
A: This calculation is specifically designed for 2-phase 4-wire underground AC transmission systems.

Q4: Are there limitations to this formula?
A: This formula assumes balanced loads and ideal conditions. Real-world systems may require additional factors for accurate calculations.

Q5: How does underground transmission differ from overhead transmission?
A: Underground transmission typically has different capacitance, inductance, and thermal characteristics that may affect power calculations.