Power Transmitted Using Volume Of Conductor Material (Two-Phase Three-Wire OS) Calculator

Formula Used:

\[ P = \sqrt{\frac{P_{\text{loss}} \times V \times (V_m \times \cos(\Phi))^2}{\rho \times ((2 + \sqrt{2}) \times L)^2}} \]

Line Losses (P_loss):

Watt

Volume Of Conductor (V):

m³

Maximum Voltage Overhead AC (V_m):

Volt

Phase Difference (Φ):

rad

Resistivity (ρ):

Ω·m

Length Of Overhead AC Wire (L):

Power Transmitted (P):

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1. What Is The Power Transmitted Using Volume Of Conductor Material (Two-Phase Three-Wire OS) Formula?

The Power Transmitted Using Volume Of Conductor Material (Two-Phase Three-Wire OS) formula calculates the power transmitted through an overhead AC line using various electrical parameters including line losses, conductor volume, maximum voltage, phase difference, resistivity, and wire length.

2. How Does The Calculator Work?

The calculator uses the formula:

\[ P = \sqrt{\frac{P_{\text{loss}} \times V \times (V_m \times \cos(\Phi))^2}{\rho \times ((2 + \sqrt{2}) \times L)^2}} \]

Where:

\( P \) — Power Transmitted (Watt)
\( P_{\text{loss}} \) — Line Losses (Watt)
\( V \) — Volume Of Conductor (m³)
\( V_m \) — Maximum Voltage Overhead AC (Volt)
\( \Phi \) — Phase Difference (rad)
\( \rho \) — Resistivity (Ω·m)
\( L \) — Length Of Overhead AC Wire (m)

Explanation: This formula calculates the power transmitted through a two-phase three-wire overhead system by considering various electrical parameters and material properties.

3. Importance Of Power Transmission Calculation

Details: Accurate power transmission calculation is crucial for designing efficient electrical distribution systems, minimizing energy losses, and ensuring proper sizing of conductors for optimal performance.

4. Using The Calculator

Tips: Enter all values in appropriate units. Ensure line losses, volume, maximum voltage, resistivity, and length are positive values. Phase difference should be in radians (0 to 2π range).

5. Frequently Asked Questions (FAQ)

Q1: What is the significance of the (2 + √2) factor in the formula?
A: This factor accounts for the specific configuration of a two-phase three-wire overhead system in the power transmission calculation.

Q2: How does conductor volume affect power transmission?
A: Larger conductor volume typically allows for better current carrying capacity and can support higher power transmission with reduced losses.

Q3: Why is phase difference important in power transmission?
A: Phase difference affects the power factor, which influences the real power transmitted through the system and the efficiency of power delivery.

Q4: What are typical resistivity values for common conductor materials?
A: Copper: ~1.68×10⁻⁸ Ω·m, Aluminum: ~2.82×10⁻⁸ Ω·m. Resistivity varies with temperature and material purity.

Q5: How does wire length impact power transmission efficiency?
A: Longer wires generally have higher resistance, leading to increased line losses and reduced power transmission efficiency over distance.