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Pressure Head Of Liquid Given Pressure Head Of Another Liquid Having Same Pressure Calculator

Formula Used:

\[ h_1 = \frac{h_2 \times w_2}{SW_1} \]

m
N/m³
N/m³

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1. What Is The Pressure Head Of Liquid Given Pressure Head Of Another Liquid Having Same Pressure?

This calculator determines the pressure head of one liquid when the pressure head of another liquid at the same pressure is known, using their specific weights. It's based on the principle that pressure at a given depth is equal in connected systems.

2. How Does The Calculator Work?

The calculator uses the formula:

\[ h_1 = \frac{h_2 \times w_2}{SW_1} \]

Where:

Explanation: The formula calculates the equivalent pressure head in liquid 1 that would produce the same pressure as the given pressure head in liquid 2, accounting for their different specific weights.

3. Importance Of Pressure Head Calculation

Details: This calculation is essential in fluid mechanics and hydraulic engineering for designing systems with multiple fluids, pressure measurement conversions, and ensuring proper pressure balancing in interconnected fluid systems.

4. Using The Calculator

Tips: Enter pressure head values in meters and specific weights in N/m³. All values must be positive numbers. The calculator will compute the equivalent pressure head in the first liquid.

5. Frequently Asked Questions (FAQ)

Q1: What is pressure head in fluid mechanics?
A: Pressure head represents the height of a liquid column that would produce the same pressure at its base. It's expressed in meters of the fluid.

Q2: Why do different liquids have different pressure heads for the same pressure?
A: Because pressure depends on both the height of the liquid column and its specific weight (density × gravity). Denser liquids require shorter columns to produce the same pressure.

Q3: What are typical units for specific weight?
A: Specific weight is typically measured in N/m³ (newtons per cubic meter) or lb/ft³ (pounds per cubic foot) in imperial units.

Q4: Can this formula be used for gases?
A: While the principle applies, gases are compressible and their density changes with pressure, making the calculation more complex than for liquids.

Q5: How accurate is this calculation for real-world applications?
A: The calculation is theoretically accurate for static fluids at the same temperature and without significant vapor pressure effects.

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