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Specific Weight Given Force Exerted By Jet On Vane In Y Direction Calculator

Formula Used:

\[ \gamma_f = \frac{F_y \cdot g}{A_{Jet} \cdot v_{jet}^2 \cdot (\sin(\theta) - \sin(\angle D))} \]

N
m/s²
m/s
rad
rad

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1. What is Specific Weight of Liquid?

Specific Weight of Liquid refers to the weight per unit volume of that substance. It is an important property in fluid mechanics that helps determine the force exerted by fluids in various applications.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ \gamma_f = \frac{F_y \cdot g}{A_{Jet} \cdot v_{jet}^2 \cdot (\sin(\theta) - \sin(\angle D))} \]

Where:

Explanation: This formula calculates the specific weight based on the force exerted by a fluid jet on a vane in the Y direction, considering the jet's cross-sectional area, velocity, and angular relationships.

3. Importance of Specific Weight Calculation

Details: Calculating specific weight is crucial for understanding fluid behavior in hydraulic systems, designing fluid machinery, and analyzing forces in jet propulsion systems.

4. Using the Calculator

Tips: Enter all values in appropriate units. Force in Newtons, acceleration in m/s², area in m², velocity in m/s, and angles in radians. All values must be positive.

5. Frequently Asked Questions (FAQ)

Q1: What is the difference between specific weight and density?
A: Specific weight is weight per unit volume (N/m³), while density is mass per unit volume (kg/m³). They are related by gravity: specific weight = density × gravity.

Q2: Why are angles measured in radians?
A: Radians are the standard unit for angular measurements in mathematical calculations, particularly when using trigonometric functions.

Q3: What are typical values for specific weight?
A: Water has a specific weight of approximately 9.81 kN/m³ at standard conditions. Other liquids vary based on their density.

Q4: When is this calculation particularly useful?
A: This calculation is essential in hydraulic engineering, turbine design, and any application involving fluid jets impacting surfaces.

Q5: What if the denominator becomes zero?
A: The calculation becomes undefined if sin(θ) equals sin(∠D). This represents a special case where the specific weight cannot be determined using this formula.

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