Stiffness Of Helical Spring Calculator

Stiffness of Helical Spring Formula:

\[ k = \frac{G \times d^4}{64 \times R^3 \times N} \]

Modulus of Rigidity of Spring (G):

Pascal

Diameter of Spring Wire (d):

Meter

Mean Radius Spring Coil (R):

Meter

Number of Coils (N):

Coils

Stiffness of Helical Spring (k):

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is Stiffness of Helical Spring?

Stiffness of Helical Spring is a measure of the resistance offered by an elastic body to deformation. Every object in this universe has some stiffness. In the context of helical springs, it represents the force required to produce unit deflection.

2. How Does the Calculator Work?

The calculator uses the stiffness formula:

\[ k = \frac{G \times d^4}{64 \times R^3 \times N} \]

Where:

\( k \) — Stiffness of Helical Spring (N/m)
\( G \) — Modulus of Rigidity of Spring (Pascal)
\( d \) — Diameter of Spring Wire (Meter)
\( R \) — Mean Radius Spring Coil (Meter)
\( N \) — Number of Coils

Explanation: The formula calculates the spring stiffness based on the material properties (modulus of rigidity), geometric dimensions (wire diameter and coil radius), and the number of active coils.

3. Importance of Spring Stiffness Calculation

Details: Accurate spring stiffness calculation is crucial for mechanical design, vibration analysis, and ensuring proper functioning of spring-based systems in various engineering applications.

4. Using the Calculator

Tips: Enter modulus of rigidity in Pascals, diameter and radius in meters, and number of coils. All values must be positive and non-zero.

5. Frequently Asked Questions (FAQ)

Q1: What is modulus of rigidity?
A: Modulus of rigidity is the elastic coefficient when a shear force is applied resulting in lateral deformation. It gives us a measure of how rigid a body is.

Q2: How does wire diameter affect spring stiffness?
A: Spring stiffness increases with the fourth power of wire diameter. Doubling the wire diameter increases stiffness by a factor of 16.

Q3: How does coil radius affect spring stiffness?
A: Spring stiffness decreases with the cube of coil radius. Doubling the coil radius decreases stiffness by a factor of 8.

Q4: How does number of coils affect spring stiffness?
A: Spring stiffness is inversely proportional to the number of coils. Doubling the number of coils halves the stiffness.

Q5: What are typical applications of helical springs?
A: Helical springs are used in automotive suspensions, mechanical watches, mattresses, and various mechanical systems where energy storage and shock absorption are required.