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Transmissivity Of Transparent Medium Given Radiosity And Shape Factor Calculator

Formula Used:

\[ \tau_m = \frac{q_{1-2 \text{ transmitted}}}{A_1 \times F_{12} \times (J_1 - J_2)} \]

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1. What is Transmissivity of Transparent Medium?

Transmissivity of Transparent Medium is the fraction of incident radiation flux transmitted through the medium. It represents how much radiation energy passes through a material without being absorbed or reflected.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ \tau_m = \frac{q_{1-2 \text{ transmitted}}}{A_1 \times F_{12} \times (J_1 - J_2)} \]

Where:

Explanation: This formula calculates the transmissivity based on the transmitted radiation heat transfer, surface area, shape factor, and the difference in radiosity between the two bodies.

3. Importance of Transmissivity Calculation

Details: Calculating transmissivity is crucial for understanding how materials interact with radiation, which is essential in thermal engineering, optical systems design, and various applications involving heat transfer through transparent media.

4. Using the Calculator

Tips: Enter all values in appropriate units. Radiation heat transfer and surface area must be positive values. The shape factor should be between 0 and 1. Radiosity values should be non-negative.

5. Frequently Asked Questions (FAQ)

Q1: What is the range of transmissivity values?
A: Transmissivity values range from 0 (completely opaque) to 1 (completely transparent), representing the fraction of radiation transmitted through the medium.

Q2: How does transmissivity differ from reflectivity and absorptivity?
A: These are the three fundamental optical properties: transmissivity (transmitted radiation), reflectivity (reflected radiation), and absorptivity (absorbed radiation). Their sum equals 1 for any material.

Q3: What factors affect transmissivity?
A: Transmissivity depends on material composition, thickness, wavelength of radiation, temperature, and surface conditions of the transparent medium.

Q4: When is this calculation particularly important?
A: This calculation is crucial in designing windows, optical filters, greenhouse covers, solar panels, and any system where radiation transmission through materials needs to be quantified.

Q5: What if the radiosity difference is zero?
A: If J₁ - J₂ = 0, the transmissivity becomes undefined as there would be no driving potential for radiation heat transfer through the medium.

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