Transmitted Power Using Area Of X-Section(Two-Wire One Conductor Earthed) Calculator

Formula Used:

\[ P = \sqrt{\frac{A \times (V_m^2) \times P_{loss}}{\rho \times L \times 2}} \]

Area of Overhead DC Wire:

m²

Maximum Voltage Overhead DC:

Line Losses:

Resistivity:

Ω·m

Length of Wire DC:

Power Transmitted:

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1. What is the Transmitted Power Formula?

The transmitted power formula calculates the power transmitted through a two-wire one conductor earthed DC system based on wire area, maximum voltage, line losses, resistivity, and wire length. It provides an accurate assessment of power transmission efficiency in overhead DC lines.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P = \sqrt{\frac{A \times (V_m^2) \times P_{loss}}{\rho \times L \times 2}} \]

Where:

\( P \) — Power Transmitted (W)
\( A \) — Area of Overhead DC Wire (m²)
\( V_m \) — Maximum Voltage Overhead DC (V)
\( P_{loss} \) — Line Losses (W)
\( \rho \) — Resistivity (Ω·m)
\( L \) — Length of Wire DC (m)

Explanation: The formula accounts for the relationship between wire characteristics, voltage, losses, and transmitted power in a DC transmission system.

3. Importance of Power Transmission Calculation

Details: Accurate power transmission calculation is crucial for designing efficient DC power systems, minimizing energy losses, and ensuring proper system capacity planning.

4. Using the Calculator

Tips: Enter all values in appropriate units (area in m², voltage in V, losses in W, resistivity in Ω·m, length in m). All values must be positive and non-zero.

5. Frequently Asked Questions (FAQ)

Q1: Why is the formula specific to two-wire one conductor earthed systems?
A: This configuration has specific electrical characteristics that differ from other wiring configurations, requiring a specialized calculation approach.

Q2: What factors affect power transmission efficiency?
A: Wire material resistivity, cross-sectional area, transmission distance, operating voltage, and system losses all impact transmission efficiency.

Q3: How does wire area affect power transmission?
A: Larger wire areas generally allow for more efficient power transmission with lower resistive losses over the same distance.

Q4: What are typical resistivity values for common conductor materials?
A: Copper: ~1.68×10⁻⁸ Ω·m, Aluminum: ~2.82×10⁻⁸ Ω·m, Silver: ~1.59×10⁻⁸ Ω·m at 20°C.

Q5: How accurate is this calculation for real-world applications?
A: The formula provides a theoretical maximum. Real-world factors like temperature variations, installation conditions, and environmental factors may affect actual performance.