Transmitted Power Using Line Losses (Two-Phase Three-Wire OS) Calculator

Formula Used:

\[ P = \sqrt{\frac{2 \times P_{\text{loss}} \times A \times (V_m \times \cos(\Phi))^2}{(2 + \sqrt{2}) \times \rho \times L}} \]

Line Losses (P_loss):

Watt

Area of Overhead AC Wire (A):

m²

Maximum Voltage Overhead AC (V_m):

Volt

Phase Difference (Φ):

Radian

Resistivity (ρ):

Ω·m

Length of Overhead AC Wire (L):

Meter

Transmitted Power (P):

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1. What is Transmitted Power Using Line Losses?

Transmitted Power Using Line Losses calculates the power delivered through a two-phase three-wire overhead system considering the losses in the transmission line. This calculation is essential for designing efficient power transmission systems.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ P = \sqrt{\frac{2 \times P_{\text{loss}} \times A \times (V_m \times \cos(\Phi))^2}{(2 + \sqrt{2}) \times \rho \times L}} \]

Where:

\( P \) — Transmitted Power (Watt)
\( P_{\text{loss}} \) — Line Losses (Watt)
\( A \) — Area of Overhead AC Wire (m²)
\( V_m \) — Maximum Voltage Overhead AC (Volt)
\( \Phi \) — Phase Difference (Radian)
\( \rho \) — Resistivity (Ω·m)
\( L \) — Length of Overhead AC Wire (Meter)

Explanation: This formula accounts for the relationship between power transmission, line losses, wire characteristics, and system parameters in a two-phase three-wire overhead system.

3. Importance of Power Transmission Calculation

Details: Accurate power transmission calculation is crucial for designing efficient electrical distribution systems, minimizing energy losses, and ensuring proper voltage levels throughout the network.

4. Using the Calculator

Tips: Enter all values in appropriate units. Ensure all inputs are positive values. The calculator will compute the transmitted power based on the provided parameters.

5. Frequently Asked Questions (FAQ)

Q1: What is the significance of the phase difference in this calculation?
A: Phase difference affects the power factor, which influences the actual power transmitted through the system versus the apparent power.

Q2: How does wire resistivity affect power transmission?
A: Higher resistivity materials cause more energy loss as heat, reducing the efficiency of power transmission.

Q3: Why is the wire area important in this calculation?
A: Larger wire cross-sectional area reduces resistance, which decreases power losses and allows for more efficient power transmission.

Q4: What are typical values for overhead AC wire resistivity?
A: Common values range from 1.68×10⁻⁸ Ω·m for copper to 2.82×10⁻⁸ Ω·m for aluminum at 20°C.

Q5: How does voltage level affect power transmission efficiency?
A: Higher transmission voltages reduce current for the same power level, which decreases I²R losses and improves transmission efficiency.