Home Back

Volume Of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) Calculator

Formula Used:

\[ V = 8 \times \rho \times \frac{P^2 \times L^2}{P_{loss} \times V_m^2 \times \cos(\Phi)^2} \]

Ω·m
W
m
W
V
rad

Unit Converter ▲

Unit Converter ▼

From: To:

1. What is Volume Of Conductor Material?

Volume Of Conductor Material refers to the 3-dimensional space enclosed by a conductor material in a 1-Phase 2-Wire Mid-Point Earthed system. It is an important parameter in electrical engineering for determining the amount of conductor material needed for underground AC transmission.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ V = 8 \times \rho \times \frac{P^2 \times L^2}{P_{loss} \times V_m^2 \times \cos(\Phi)^2} \]

Where:

Explanation: This formula calculates the required volume of conductor material based on system parameters and electrical properties.

3. Importance of Volume Calculation

Details: Accurate volume calculation is crucial for material estimation, cost calculation, and efficient design of underground electrical systems. It helps in optimizing conductor size and minimizing material waste.

4. Using the Calculator

Tips: Enter all values in appropriate units. Resistivity in Ω·m, power in watts, length in meters, losses in watts, voltage in volts, and phase difference in radians. All values must be positive.

5. Frequently Asked Questions (FAQ)

Q1: Why is conductor volume important in electrical systems?
A: Conductor volume determines the amount of material needed, affects system cost, and influences the electrical performance and efficiency of the transmission system.

Q2: What factors affect the volume of conductor material?
A: The volume depends on resistivity, transmitted power, wire length, allowable losses, system voltage, and power factor (phase difference).

Q3: How does phase difference affect conductor volume?
A: A lower power factor (higher phase difference) requires more conductor volume to transmit the same amount of power with the same losses.

Q4: What are typical resistivity values for common conductor materials?
A: Copper: 1.68×10⁻⁸ Ω·m, Aluminum: 2.82×10⁻⁸ Ω·m, Silver: 1.59×10⁻⁸ Ω·m, Gold: 2.44×10⁻⁸ Ω·m.

Q5: How can I reduce the required conductor volume?
A: By increasing system voltage, improving power factor, reducing transmission distance, or using materials with lower resistivity.

Volume Of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) Calculator© - All Rights Reserved 2025