Work Done Per Second For Centrifugal Pumps Calculator

Formula Used:

\[ \text{Work Done by Pump Per Second} = \frac{\text{Weight of Liquid in Pump}}{[g]} \times \text{Velocity of Whirl at Outlet} \times \text{Tangential Velocity of Impeller at Outlet} \] \[ W = \frac{Wl}{[g]} \times Vw2 \times u2 \]

Weight of Liquid in Pump:

Velocity of Whirl at Outlet:

m/s

Tangential Velocity of Impeller at Outlet:

m/s

Work Done by Pump Per Second:

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1. What is Work Done Per Second For Centrifugal Pumps?

Work Done Per Second For Centrifugal Pumps represents the amount of energy transferred by the pump to the fluid per unit time. It quantifies the pump's power output in terms of the hydraulic work performed on the fluid.

2. How Does the Calculator Work?

The calculator uses the formula:

\[ W = \frac{Wl}{[g]} \times Vw2 \times u2 \]

Where:

\( W \) — Work Done by Pump Per Second (J)
\( Wl \) — Weight of Liquid in Pump (N)
\( [g] \) — Gravitational acceleration (9.80665 m/s²)
\( Vw2 \) — Velocity of Whirl at Outlet (m/s)
\( u2 \) — Tangential Velocity of Impeller at Outlet (m/s)

Explanation: This formula calculates the work done per second by considering the mass flow rate (derived from weight divided by gravity) and the velocity components that contribute to the energy transfer in the centrifugal pump.

3. Importance of Calculating Work Done

Details: Calculating work done per second is essential for determining pump efficiency, sizing motors, evaluating pump performance, and ensuring optimal energy usage in fluid systems.

4. Using the Calculator

Tips: Enter the weight of liquid in Newtons, velocity of whirl at outlet in m/s, and tangential velocity of impeller at outlet in m/s. All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What is the significance of the velocity of whirl?
A: The velocity of whirl represents the tangential component of absolute velocity at the blade outlet, which directly contributes to the angular momentum transfer and thus the work done by the pump.

Q2: Why do we divide by gravitational acceleration?
A: Dividing weight by gravitational acceleration converts the weight force to mass, which is necessary for calculating the mass flow rate in the work equation.

Q3: How does this relate to pump power requirements?
A: The work done per second is essentially the theoretical power output of the pump. Comparing this to the actual power input allows calculation of pump efficiency.

Q4: What are typical values for tangential velocity?
A: Tangential velocity depends on impeller diameter and rotational speed, typically ranging from 10-50 m/s for most centrifugal pumps.

Q5: Can this formula be used for all pump types?
A: This specific formula is designed for centrifugal pumps. Other pump types (positive displacement, axial flow) have different working principles and require different calculations.